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Amaranth · Thales Joined: 19 Oct 2008 Posts: 128

Unghiurile complementare sunt 2 unghiuri adacente care au suma masurilor 90*.

Unghiul AOB complementul lui unghiului BOC.
Care este masura lui AOB^ daca m(BOC^)= 59* 59' 59''? Wink

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naruto · Pitagora Joined: 14 Oct 2008 Posts: 55

$1^\circ$ =60'=60 $\cdot$ 60''=3600''

In problema noastra
59''+1''=60"=1'
59'+1'=60'= $1^\circ$
$59^\circ+1^\circ=60^\circ$
$90^\circ-60^\circ=30^\circ$

Deci complementul este $30^\circ$ +1''.

Numerele de la unghiuri seamana cu niste numere in baza 60 in loc de baza 10 Very Happy

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The important thing is not to stop questioning. Albert Einstein.

naruto · Pitagora Joined: 14 Oct 2008 Posts: 55

Cum se pot scrie minutele si secundele in LaTeX? Vad ca nu apar deloc cand le scrii cu TeX.
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The important thing is not to stop questioning. Albert Einstein.

Amaranth · Thales Joined: 19 Oct 2008 Posts: 128

Nu prea stiu... felicitari ca nu ai cazut in plasa in care cad toti: ei scriu 1"... Darare 90*... Si 1" ar fi 60* Wink

_________________
In all this world there is only one pure and magic thing... and it is called PURPLE!

miruna.lazar · Bernoulli Joined: 08 Oct 2008 Posts: 224 Location: Tulcea

90*- 59*59'59"= 89*59'60"- 59*59'59" = 30*0'1"= 30*1"
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