Progresie aritmetica

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Al3x
Posts: 1
Joined: Wed Nov 12, 2008 8:16 pm

Progresie aritmetica

Post by Al3x »

\( a_2+a_{40}=16 \)
\( a_5=28 \)
\( a_1=?,\ r=? \)
Alin
Euclid
Posts: 14
Joined: Sat Mar 27, 2010 12:57 pm

Post by Alin »

\( \ a_2+\ a_{40}=16 \) adica \( \ 2a_1+40r=16 => \ a_1+20r=8 (1) \). Din \( \ a_5=28 \) scoatem \( \ a_1+4r=28 (2) \). Din \( (1), (2) => 16r=-20 => r=-\frac {20}{16}=-\frac {5}{4} \). Stim ratia si \( \ a_5=28 \) si aflam ca \( \ a_1=33 \).
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