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Calcul de integrala 4

Posted: Mon Feb 04, 2008 2:54 am
by Kunihiko Chikaya
Sa se calculeze

\( \int_0^1 (1+2008x^{2008})e^{x^{2008}}dx. \)

Kunihiko Chikaya

Posted: Fri Feb 06, 2009 9:20 pm
by Marius Mainea
\( \int_0^1 (1+2008x^{2008})e^{x^{2008}}dx=xe^{x^{2008}}|_0^1=e \)