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Ecuatie simpla, cu o forma interesanta
Posted: Tue Sep 23, 2008 7:05 pm
by Ciprian Oprisa
Sa se rezolve ecuatia:
\( x^{x^{\ldots^x}} = 2 \)
Posted: Tue Sep 30, 2008 10:05 am
by Laurian Filip
pt ca ecuatia sa aiba sens sirul trebuie sa fie convergent.
fie \( \lim_{n\to\infty}x_n=l \)
\( l=2 \)
\( x^l=2 \)
de unde \( x=\sqrt{2} \)