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Multimi
Posted:
Tue Oct 21, 2008 8:32 pm
by
Marcelina Popa
Sa se determine multimea:
\(
A=\{x\in [-1,1]/\frac{2x-1}{3}\in \mathbb{Z}\} \)
Posted:
Wed Oct 22, 2008 12:49 pm
by
mihai++
\( -1\leq x\leq1\Rightarrow -3\leq2x-1\leq1\Rightarrow -1\leq\frac{2x-1}{3}\leq\frac{1}{3}\Rightarrow 2x-1\in\{0,-3\}\Rightarrow A=\{\frac{1}{2},-1} \)