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TMMATE problema 1

Posted: Mon Jan 26, 2009 3:25 pm
by Beniamin Bogosel
Determinati ultimele 2 cifre ale numarului \( A=1^2-2^2+3^2-4^2+...+2007^2-2008^2+2009^2 \).

TMMATE 2009

Posted: Sun Feb 01, 2009 11:13 pm
by Marius Mainea
\( A=1005\cdot 2009 \)