Inecuatie logaritmica
Posted: Tue Jan 27, 2009 12:43 pm
Sa se determine x, y\( \in(0,1) \), stiind ca:
\( \log_{x} \frac{3xy}{2xy+x+y}+\log_{y}\frac{3xy}{2xy+x+y}+\log_{\frac{1}{2}}\frac{3xy}{2xy+x+y}\leq 3. \)
\( \log_{x} \frac{3xy}{2xy+x+y}+\log_{y}\frac{3xy}{2xy+x+y}+\log_{\frac{1}{2}}\frac{3xy}{2xy+x+y}\leq 3. \)