Suma Riemann sau poate nu!
Posted: Thu Jan 21, 2010 11:27 pm
Calculati:
\( {\lim }\limits_{t \to \infty } \int\limits_0^t {\frac{1}{{\left( {x^2 + 1} \right)\left( {x^2 + 4} \right)\left( {x^2 + 9} \right) \ldots \left( {x^2 + n^2 } \right)}}dx} \)
\( {\lim }\limits_{t \to \infty } \int\limits_0^t {\frac{1}{{\left( {x^2 + 1} \right)\left( {x^2 + 4} \right)\left( {x^2 + 9} \right) \ldots \left( {x^2 + n^2 } \right)}}dx} \)