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Aflati functia !
Posted: Tue Mar 02, 2010 10:30 pm
by katos
Fie f,g:R definite in R doua functii astfel incat :
sistem : f(1-x)+g(2x-4)=4x-11
f(3x+1)+g(-6x-4)=-30x-25 oricare x e R
a)determinati f si g
b)rezolvati (2x-1)f(x)+(2+3x)g(x)=11^2 +5x-7
c)rezolvati ecuatia
f(x+2/x-1)+g(1-x/1+x)+2=7/x-1 , (xdiferit de -+1)
Posted: Tue Mar 02, 2010 11:12 pm
by Laurentiu Tucaa
Esti sigur ca asta era enuntul?pt x=0 avem \( f(1)+g(-4)=-11 \) din prima ec a sist si \( f(1)+g(-4)=-25 \) ,deci sistemul este incompatibil .
Posted: Wed Mar 03, 2010 8:48 am
by katos
Laurentiu Tucaa wrote:Esti sigur ca asta era enuntul?pt x=0 avem \( f(1)+g(-4)=-11 \) din prima ec a sist si \( f(1)+g(-4)=-25 \) ,deci sistemul este incompatibil .
e corect enuntul
Posted: Wed Mar 03, 2010 6:57 pm
by Laurentiu Tucaa
katos wrote:Laurentiu Tucaa wrote:Esti sigur ca asta era enuntul?pt x=0 avem \( f(1)+g(-4)=-11 \) din prima ec a sist si \( f(1)+g(-4)=-25 \) ,deci sistemul este incompatibil .
e corect enuntul
de cand -11=-25?
Posted: Wed Mar 03, 2010 7:45 pm
by katos
Laurentiu Tucaa wrote:katos wrote:Laurentiu Tucaa wrote:Esti sigur ca asta era enuntul?pt x=0 avem \( f(1)+g(-4)=-11 \) din prima ec a sist si \( f(1)+g(-4)=-25 \) ,deci sistemul este incompatibil .
e corect enuntul
de cand -11=-25?
asa e in carte
