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Partea Intreaga
Posted: Fri Mar 12, 2010 4:22 pm
by Robert_Samoilescu95
Sa se rezolve in R ecuatia :X^6-2[X]^3+1 =0
Posted: Fri Mar 12, 2010 4:46 pm
by Virgil Nicula
\( [x]\le x\ \Longrightarrow\ [x]^3\le x^3 \) . Asadar, \( 0\le \left(x^3-1\right)^2=-2\left(x^3-[x]^3\right)\le 0\ \Longrightarrow\ x=1 \) care verifica ecuatia initiala.