Calcul de integrala 4

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Kunihiko Chikaya
Arhimede
Posts: 7
Joined: Sun Feb 03, 2008 7:06 pm
Location: Tokio

Calcul de integrala 4

Post by Kunihiko Chikaya »

Sa se calculeze

\( \int_0^1 (1+2008x^{2008})e^{x^{2008}}dx. \)

Kunihiko Chikaya
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Marius Mainea
Gauss
Posts: 1077
Joined: Mon May 26, 2008 2:12 pm
Location: Gaesti (Dambovita)

Post by Marius Mainea »

\( \int_0^1 (1+2008x^{2008})e^{x^{2008}}dx=xe^{x^{2008}}|_0^1=e \)
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