Limita

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Francisc
Euclid
Posts: 12
Joined: Thu Oct 04, 2007 9:36 am
Location: Timisoara

Limita

Post by Francisc »

Sa se calculeze limita sirului :
\(
{\lim }\limits_{n \to \infty } \frac{1}{{n^2 }}\sum\limits_{k = 0}^{n - 1} {\sqrt {3k^2 + 3k + 1 + \frac{{n^2 }}{{a^2 }}} }
\ \)
, unde a>0.
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