multime cu submultimi disjuncte

handleman · Post by **handleman** » Thu Mar 20, 2008 5:35 pm

Fiind data multimea A={3;4;5;...;30} aratati ca:
a)Exista 14 submultimi ale multimii A, disjuncte doua cate doua, fiecare fiind formata din doua elemente, iar suma acestor elemente sa fie patrat perfect.
b)Elementele multimii A nu pot fi aranjate pe un cerc astfel incat suma oricaror doua numere vecine sa fie patrat perfect.

marius00 · Post by **marius00** » Thu Mar 20, 2008 10:42 pm

a) {3,6};{4,5};(7,18};{8,17};{10,15};{11,14};{12,13};{9,16};{19,30};{21,28};
{22,27};{23,26};{24,25};{20,29}

handleman · Post by **handleman** » Fri Mar 21, 2008 5:32 pm

sa fiu sincer astai nui rezolvare completa
uite :3+4=7
29+30=59
=>P.P.apartine{9;16;25;36;49}
3+4+5+6+...+30=462
abia dupaia INCepe cautarea

marius00 · Post by **marius00** » Fri Mar 21, 2008 9:38 pm

de vreme ce ti-am gasit cele 14 submultimi inseamna ca ele exista sau ma insel ?

handleman · Post by **handleman** » Sat Mar 22, 2008 1:40 pm

nu dar trebuie sa scrii toooot