o ecuatie cam grea!!

[george93]

aflati x din ecuatia:x-2003 supra 5 +x-1999 supra 9+ x-1995 supra 13+......+ x-1951 supra 57=14.

[thekrisser]

Dc x>=2008 =>
x-2003>=5
x-1999>=9
.
.
.
x-1951>=57
=>
(x-2003) / 5 >= 1
(x-1999) / 9 >= 1
.
.
.
(x-1951 )/ 57 >=1
Adunand relatiile obtinem
(x-2003)/5 + (x-1999) / 9 +.... + (x-1951)/51 >=14

Analog dc x<=2008 => Suma <=14
Dc x natural => x=2008