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george93
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It turned out great for your first go at it Mike! One secret I use before I curl my dolls hair is I trim the hair ends, especially if its Rock N Curl Jem, lol Talk about one doll with split ends, its
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maxim bogdan
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Post by maxim bogdan »

Este o problema clasica de teoria grafurilor. Consideram graful \( G=(V;E) \), cu \( |G|=n \),\( ||G||=m \) . Ducem muchie intre varfurile \( i \) si \( j \) daca \( i \) l-a salutat pe \( j \).(Daca \( i \) l-a salutat pe \( j \), atunci si \( j \) l-a salutat pe \( i! \)). Notam cu \( d(i) \) numarul de persoane pe care le-a salutat \( i \). Evident: \( \sum_{i} d(i)=2m. \)

Dar \( \sum_{i} d(i)=\sum_{d(i)-par} d(i)+\sum_{d(j)-impar} d(j)=2m. \)
Deci \( \sum_{d(j)-impar} d(j) \) este para. Deci numarul persoanelor care saluta un numar impar de persoane este par.
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Bogdan Cebere
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