Doua probleme nerezolvate

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Merqs
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Doua probleme nerezolvate

Post by Merqs »

Prima ar fi:

1. z1,z2,z3 apartin numerelor complexe.
|z1|=|z2|=|z3|=1
z1+z2+z3=-i
a)Calculati (z1+i)(z2+i)(z3+i)

b)S=z1 la puterea 2007+z2 la puterea 2007+z3 la puterea 2007


Si a doua problema

2.Fie a,b,c>1 cu proprietatea ca 2*\( \log_{ab} \)=1+\( \log_{ac} \)
Demonstrati ca:

1-\( \log_{abc}(bc) \); 1-\( \log_{bca}(ac) \); 1-\( \log_{cba}(ab) \) sunt in progresie aritmetica

Va multumesc
Last edited by Merqs on Sun Jan 18, 2009 8:48 pm, edited 2 times in total.
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Laurian Filip
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Post by Laurian Filip »

mersi
Last edited by Laurian Filip on Mon Jan 19, 2009 4:53 pm, edited 1 time in total.
andy crisan
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Post by andy crisan »

se conjuga \( z_1+z_2+z_3=-i \) si se obtine folosind faptul ca \( z\overline{z}=|z|^2=1 \) in cazul nostru si obtinem ca \( z_1z_2+z_2z_3+z_3z_1=iz_1z_2z_3 \) se desfac parantezele si obtii in final folosind relatia anterioara si cea din enunt ca P=0 asta pt a
pt b) ai asa din P=0 \( \Rightarrow \)ca unul din \( z_1,z_2,z_3=-i \) si consideram \( z_1=-i \) in celelalte cazuri procedandu-se analog \( \Rightarrow z_2+z_3=0\Rightarrow z_2=-z_3 \Rightarrow z_2^{2007}=-z_3^{2007} si z_1^{2007}= -i^{2007}=-i^3=i \Rightarrow S=i \) problema asta e de clasa nu de olimpiade
Last edited by andy crisan on Mon Jan 19, 2009 10:59 pm, edited 5 times in total.
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