Inegalitate

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BogdanCNFB
Thales
Posts: 121
Joined: Wed May 07, 2008 4:29 pm
Location: Craiova

Inegalitate

Post by BogdanCNFB »

Fie \( a_1,a_2,...,a_n>0 \) si \( n\in N^* \). Aratati ca:
\( \sum_{k=1}^na_k^k\ge n+\sum_{k=1}^na_k\cdot k-\sum_{k=1}^nk \).
Marius Mainea
Gauss
Posts: 1077
Joined: Mon May 26, 2008 2:12 pm
Location: Gaesti (Dambovita)

Post by Marius Mainea »

Se alica metoda inductiei matematice folosind inegalitatea lui Bernoulli:
\( (1+x)^n\geq1+nx, \ pentru \ x\geq-1 ,n\in N \)
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