Se considera relatia de echivalenta pe \( \mathbb{R} \):
\( x\sim y \Leftrightarrow x-y \in \mathbb{Q} \).
Demonstrati ca numarul claselor de echivalenta este \( c=card\ \mathbb{R} \).
Clase de echivalenta
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Clase de echivalenta
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Alegem o baza a spatiului vectorial \( \mathbb{R} \) peste \( \mathbb{Q} \) (asta avand dimensiunea c), care il contine pe 1. (Exista o teorema, care ne permite acest lucru, o consecinta a axiomei alegerii.) Daca luam doua elemente ale bazei, x si y, ele sigur se afla in clase de echivalenta diferite. In caz contrar am obtine \( x-y=q\cdot 1 \), unde \( q \in \mathbb{Q} \), deci cele trei elemente ale bazei \( 1, x, y \) sunt liniar dependente, contradictie. In concluzie numarul claselor de echivalenta este \( \ge \) dimensiunea bazei \( =c \) si clar \( \le card \,\mathbb{R}=c \).
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E adevarat ca o baza Hamel este de puterea continuumului? Exista vreo demonstratie?
Yesterday is history,
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Tomorow is a mistery,
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