OJM 2010 Problema III

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Andi Brojbeanu
Bernoulli
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OJM 2010 Problema III

Post by Andi Brojbeanu »

Se considera triunghiul \( ABC \) cu \( AB=AC \) si \( \angle{BAC}=40\textdegree \). Punctele \( S \) si \( T \) se afla pe laturile \( AB \), respectiv \( BC \), astfel incat \( \angle{BAT}=\angle{BCS}=10\textdegree \). Dreptele \( AT \) si \( CS \) se intersecteaza in punctul \( P \). Demonstrati ca \( BT=2PT \).
Gabriel Popa
Andi Brojbeanu
profesor, Liceul Teoretic "Lucian Blaga", Cluj-Napoca
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