ab+bc+ca=1

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Claudiu Mindrila
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ab+bc+ca=1

Post by Claudiu Mindrila »

Daca \( a,b,c \in (0, \infty) \) astfel incat \( ab+bc+ca=1 \), atunci \( abc(a+\sqrt{a^2+1})(b+\sqrt{b^2+1})(c+\sqrt{c^2+1}) \le 1 \).
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Marius Mainea
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Post by Marius Mainea »

\( LHS=\prod {\frac{a}{\sqrt{a^2+1}-a}}=\prod{\frac{a}{\sqrt{(a+b)(a+c)}-a}}\le\prod{\frac{a}{a+\sqrt{bc}-a}}=\prod{\frac{a}{\sqrt{bc}}=1=RHS \)
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