ab+bc+ca=1
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Claudiu Mindrila
- Fermat
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ab+bc+ca=1
Daca \( a,b,c \in (0, \infty) \) astfel incat \( ab+bc+ca=1 \), atunci \( abc(a+\sqrt{a^2+1})(b+\sqrt{b^2+1})(c+\sqrt{c^2+1}) \le 1 \).
elev, clasa a X-a, C. N. "C-tin Carabella", Targoviste
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Marius Mainea
- Gauss
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